Identify Z in the following series of reactio | vedclass

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(C) The reaction sequence is as follows:$1$. Dehydration of ethanol $(CH_3-CH_2-OH)$ with concentrated $H_2SO_4$ at $170^{\circ} C$ gives ethene $(X)$

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$CH_3-C \equiv CH$

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(C) The reaction sequence is as follows:$1$. Dehydration of ethanol $(CH_3-CH_2-OH)$ with concentrated $H_2SO_4$ at $170^{\circ} C$ gives ethene $(X)$: $CH_3-CH_2-OH \xrightarrow{conc. H_2SO_4, 170^{\circ} C} CH_2=CH_2 (X) + H_2O$$2$. Addition of $Br_2$ in $CCl_4$ to ethene gives $1,2-$dibromoethane $(Y)$:$CH_2=CH_2 + Br_2 \xrightarrow{CCl_4} CH_2Br-CH_2Br (Y)$$3$. Dehydrohalogenation of $1,2-$dibromoethane with alcoholic $KOH$ followed by heating gives ethyne $(Z)$:$CH_2Br-CH_2Br \xrightarrow{alc. KOH, \Delta} CH \equiv CH (Z) + 2HBr$Note: The provided options seem to contain structures for propene derivatives. However,based on the starting material ethanol,the final product $Z$ is ethyne $(HC \equiv CH)$. If the starting material was meant to be propan$-1-$ol,the product would be propyne. Given the options,$C$ represents propyne,which is the homologue of the expected product.

Identify $Z$ in the following series of reaction:
$CH_3-CH_2-OH$ $\xrightarrow[170^{\circ} C]{conc. H_2SO_4} X$ $\xrightarrow[CCl_4]{Br_2} Y$ $\xrightarrow[\Delta]{alc. KOH} Z$

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Identify $Z$ in the following series of reaction:$CH_3-CH_2-OH$ $\xrightarrow[170^{\circ} C]{conc. H_2SO_4} X$ $\xrightarrow[CCl_4]{Br_2} Y$ $\xrightarrow[\Delta]{alc. KOH} Z$