(B) Coulomb's law describes the electrostatic force between charged particles. $A$,$C$,and $D$ involve electrostatic interactions (attraction between

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Binds the protons and neutrons in the nucleus of an atom

(B) Coulomb's law describes the electrostatic force between charged particles. $A$,$C$,and $D$ involve electrostatic interactions (attraction between electrons and nuclei,or between atoms/molecules). However,the force that binds protons and neutrons (nucleons) within the nucleus is the strong nuclear force,which is not an electric force. Therefore,the statement in option $B$ is incorrect.

Class 12 Physics Electric Charges and Fields Electrostatic Force and Coulombs Law

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Identify the wrong statement in the following. Coulomb's law correctly describes the electric force that

A
Binds the electrons of an atom to its nucleus
B
Binds the protons and neutrons in the nucleus of an atom
C
Binds atoms together to form molecules
D
Binds atoms and molecules together to form solids

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Class 12 Questions

Class 12

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Electric Charges and Fields

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Electrostatic Force and Coulombs Law

The ratio of gravitational force and electrostatic repulsive force between two electrons is approximately (gravitational constant $= 6.7 \times 10^{-11} \, Nm^2/kg^2$,mass of an electron $= 9.1 \times 10^{-31} \, kg$,charge on an electron $= 1.6 \times 10^{-19} \, C$).

MediumKVPY 2020

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$A$ point charge $Q$ is placed at the center of the line joining two equal point charges $+q$ and $+q$. The value of $Q$ if the system of the charges is in equilibrium,is

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Two point charges $3 \times 10^{-6} \, C$ and $8 \times 10^{-6} \, C$ repel each other by a force of $6 \times 10^{-3} \, N$. If each of them is given an additional charge $-6 \times 10^{-6} \, C$,the force between them will be

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Two particles of equal mass $m$ and charge $q$ are placed at a distance of $16 \, cm$. They do not experience any net force. The value of $\frac{q}{m}$ is

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For the system shown in the figure,find $Q$ such that the resultant force on $q$ is zero.

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Identify the wrong statement in the following. Coulomb's law correctly describes the electric force that

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The ratio of gravitational force and electrostatic repulsive force between two electrons is approximately (gravitational constant $= 6.7 \times 10^{-11} \, Nm^2/kg^2$,mass of an electron $= 9.1 \times 10^{-31} \, kg$,charge on an electron $= 1.6 \times 10^{-19} \, C$).

$A$ point charge $Q$ is placed at the center of the line joining two equal point charges $+q$ and $+q$. The value of $Q$ if the system of the charges is in equilibrium,is

Two point charges $3 \times 10^{-6} \, C$ and $8 \times 10^{-6} \, C$ repel each other by a force of $6 \times 10^{-3} \, N$. If each of them is given an additional charge $-6 \times 10^{-6} \, C$,the force between them will be

Two particles of equal mass $m$ and charge $q$ are placed at a distance of $16 \, cm$. They do not experience any net force. The value of $\frac{q}{m}$ is

For the system shown in the figure,find $Q$ such that the resultant force on $q$ is zero.

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