Identify the total number of carbon atoms present in undecane.
- A$9$
- B$11$
- C$10$
- D$20$
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Identify the final product $C$ in the following reaction sequence:
$Br-(CH_2)_5-Br$ $\xrightarrow{Na, \text{D.E.}} A$ $\xrightarrow{Br_2, \Delta} B$ $\xrightarrow{\text{alc. KOH}, \Delta} C$
$Br-(CH_2)_5-Br$ $\xrightarrow{Na, \text{D.E.}} A$ $\xrightarrow{Br_2, \Delta} B$ $\xrightarrow{\text{alc. KOH}, \Delta} C$
The $C-H$ bond distance is longest in
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View SolutionComplete the reactions:
$1. CH_4 + O_2 \xrightarrow{Mn_2O_3, \Delta} ?$
$2. CH_3CH_3 + O_2 \xrightarrow{(CH_3COO)_2Mn, \Delta} ?$
$1. CH_4 + O_2 \xrightarrow{Mn_2O_3, \Delta} ?$
$2. CH_3CH_3 + O_2 \xrightarrow{(CH_3COO)_2Mn, \Delta} ?$
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View Solution$(CH_3)_2CHBr$ $\xrightarrow[(2) CuI]{(1) Li} (A)$ $\xrightarrow{(CH_3)_2CHCH_2Br} B$.
$'B'$ is
$'B'$ is
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View SolutionWhich of the following compounds can be best prepared by Wurtz reaction?
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