Identify the reductant in the following react | vedclass

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Question

(C) The oxidation states of the elements in the reaction are: $\stackrel{+3}{C_2}O_4^{2-} + \stackrel{+7}{Mn}O_4^{-} + H^{+}$ $\longrightarrow \stackr

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$C_2O_4^{2-}$

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(C) The oxidation states of the elements in the reaction are: $\stackrel{+3}{C_2}O_4^{2-} + \stackrel{+7}{Mn}O_4^{-} + H^{+}$ $\longrightarrow \stackrel{+2}{Mn^{2+}} + \stackrel{+4}{C}O_2 + H_2O$. In this reaction,the oxidation number of carbon $(C)$ increases from $+3$ in $C_2O_4^{2-}$ to $+4$ in $CO_2$. Since the oxidation number increases,$C_2O_4^{2-}$ undergoes oxidation and acts as the reducing agent (reductant).

Identify the reductant in the following reaction: $C_2O_4^{2-} + MnO_4^{-} + H^{+} \longrightarrow Mn^{2+} + CO_2 + H_2O$

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