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(C) The reaction of $n$-hexane $(CH_{3}-(CH_{2})_{4}-CH_{3})$ in the presence of $Cr_{2}O_{3}$ supported on alumina at $773 \ K$ and $10-20 \ atm$ pre

Vedclass · Accepted Answer

$C_{6}H_{6} + 4 \ H_{2}$

Vedclass · Answer

(C) The reaction of $n$-hexane $(CH_{3}-(CH_{2})_{4}-CH_{3})$ in the presence of $Cr_{2}O_{3}$ supported on alumina at $773 \ K$ and $10-20 \ atm$ pressure is known as aromatization or catalytic reforming.In this process,$n$-hexane undergoes cyclization and dehydrogenation to form benzene $(C_{6}H_{6})$ and hydrogen gas $(H_{2})$.The balanced chemical equation is:$CH_{3}-(CH_{2})_{4}-CH_{3} \xrightarrow{Cr_{2}O_{3}, 773 \ K, 10-20 \ atm} C_{6}H_{6} + 4 \ H_{2}$Thus,the product $X$ is $C_{6}H_{6} + 4 \ H_{2}$.

Identify the product $X$ obtained in the following reaction:
$CH_{3}-(CH_{2})_{4}-CH_{3} \xrightarrow{Cr_{2}O_{3}, 773 \ K, 10-20 \ atm} X$

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Identify the product $X$ obtained in the following reaction:$CH_{3}-(CH_{2})_{4}-CH_{3} \xrightarrow{Cr_{2}O_{3}, 773 \ K, 10-20 \ atm} X$