Identify the products A, B, C, D in the react | vedclass

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(C) $1$. In reaction $(X)$,the electrolysis of aqueous $NaCl$ (brine) produces $NaOH$ $(A)$,$H_2$ gas $(B)$,and $Cl_2$ gas.$2NaCl(aq) + 2H_2O(l) \righ

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$NaOH, H_2, NaCl, NaClO_3$

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(C) $1$. In reaction $(X)$,the electrolysis of aqueous $NaCl$ (brine) produces $NaOH$ $(A)$,$H_2$ gas $(B)$,and $Cl_2$ gas.$2NaCl(aq) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g) + Cl_2(g)$.Thus,$A = NaOH$ and $B = H_2$.$2$. The reaction of $NaOH$ $(A)$ with $Al$ produces sodium aluminate $(NaAlO_2)$ and $H_2$ $(B)$: $2Al + 2NaOH + 2H_2O \rightarrow 2NaAlO_2 + 3H_2$.$3$. In reaction $(Y)$,$NaOH$ $(A)$ reacts with $Cl_2$ at hot and concentrated conditions to produce $NaCl$ $(C)$ and $NaClO_3$ $(D)$:$6NaOH + 3Cl_2 \rightarrow 5NaCl + NaClO_3 + 3H_2O$.Therefore,$A = NaOH, B = H_2, C = NaCl, D = NaClO_3$.

Identify the products $A, B, C, D$ in the reactions given below:
$(X) \ NaCl \xrightarrow{\text{Aq. Electrolysis}} A + B(g) + Cl_2$
$A + Al \rightarrow NaAlO_2 + B(g)$
$(Y) \ A + Cl_2 \rightarrow C + D + H_2O$

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Identify the products $A, B, C, D$ in the reactions given below:$(X) \ NaCl \xrightarrow{\text{Aq. Electrolysis}} A + B(g) + Cl_2$$A + Al \rightarrow NaAlO_2 + B(g)$$(Y) \ A + Cl_2 \rightarrow C + D + H_2O$