Identify the major product formed in the foll | vedclass

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(A) The reaction of $3-$bromo$-2-$methylpentane with alcoholic $KOH$ is a dehydrohalogenation reaction ($E2$ mechanism). According to Saytzeff's rule,

Vedclass · Accepted Answer

$2-$Methylpent$-2-$ene

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(A) The reaction of $3-$bromo$-2-$methylpentane with alcoholic $KOH$ is a dehydrohalogenation reaction ($E2$ mechanism). According to Saytzeff's rule,the major product is the more substituted alkene. The starting material is $CH_3-CH(CH_3)-CH(Br)-CH_2-CH_3$. Removal of $H$ from $C-2$ gives $CH_3-C(CH_3)=CH-CH_2-CH_3$ ($2-$methylpent$-2-$ene). Removal of $H$ from $C-4$ gives $CH_3-CH(CH_3)-CH=CH-CH_3$ ($4-$methylpent$-2-$ene). $2-$Methylpent$-2-$ene is more substituted (trisubstituted) compared to $4-$methylpent$-2-$ene (disubstituted),hence it is the major product.

Identify the major product formed in the following reaction: $3-$Bromo$-2-$methylpentane $\xrightarrow{Alc. KOH, \Delta}$ Major product

Similar Questions

The order of reactivity of the following halides towards $S_{N}1$ reaction is:
$(1) \ (CH_3)_3CBr$
$(2) \ (C_6H_5)_2CHBr$
$(3) \ (C_6H_5)_2C(CH_3)Br$
$(4) \ (CH_3)_2CHBr$
$(5) \ C_2H_5Br$

Among the given halides,which one will give the same product in both $S_{N^1}$ and $S_{N^2}$ reactions?
$(I) \ CH_3-CH(CH_3)-CH_2-CH(Br)-CH_3$
$(II) \ \text{2-methylcyclohexyl chloride}$
$(III) \ \text{Chlorocyclohexane}$
$(IV) \ CH_3-CH(Br)-CH_2-CH_3$

What are reactant $X$ and product $Y$ in the following sequence of reactions?
Reactant $X$ $\xrightarrow{\text{Pyridine, } CH_3C_6H_4SO_2Cl}$ Intermediate $\xrightarrow{NaN_3, \text{Ethanol-water}}$ Product $Y$

The principal organic product of the reaction will be:

Write the mechanism of the following reaction:
$n-BuBr + KCN \xrightarrow{EtOH/H_2O} n-BuCN$

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