Identify the isoelectronic pair from the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Isoelectronic species are those that have the same number of electrons.$1$. For $Ne$ $(Z=10)$: Electrons = $10$. For $O^{2-}$ $(Z=8)$: Electrons =

Vedclass · Accepted Answer

$Ne$ and $O^{2-}$

Vedclass · Answer

(A) Isoelectronic species are those that have the same number of electrons.$1$. For $Ne$ $(Z=10)$: Electrons = $10$. For $O^{2-}$ $(Z=8)$: Electrons = $8 + 2 = 10$. Both have $10$ electrons,so they are isoelectronic.$2$. For $Cl^{-}$ $(Z=17)$: Electrons = $17 + 1 = 18$. For $Ca$ $(Z=20)$: Electrons = $20$. Not isoelectronic.$3$. For $Ar$ $(Z=18)$: Electrons = $18$. For $F^{-}$ $(Z=9)$: Electrons = $9 + 1 = 10$. Not isoelectronic.$4$. For $K^{+}$ $(Z=19)$: Electrons = $19 - 1 = 18$. For $Al^{3+}$ $(Z=13)$: Electrons = $13 - 3 = 10$. Not isoelectronic.Therefore,the correct pair is $Ne$ and $O^{2-}$.

Identify the isoelectronic pair from the following.

Similar Questions

The atomic number of an element is always equal to

The spectrum of Helium is expected to be similar to that of . . . . . .

Symbols $_{35}^{79} Br$ and $^{79} Br$ can be written,whereas symbols $_{79}^{35} Br$ and $^{35} Br$ are not acceptable. Answer briefly.

Write the complete symbol for the atom with the given atomic number $(Z)$ and atomic mass $(A)$:
$(i)$ $\quad Z=17, A=35$
$(ii)$ $\quad Z=92, A=233$
$(iii)$ $\quad Z=4, A=9$

If the number of neutrons in $_{8}O^{16}$ is doubled and the number of electrons is halved,what is the percentage change in its mass?

Vedclass Test Series

Exam Paper Generator

Online Exam Module