(A) In $CrO_{4}^{2-}$,the oxidation state of $Cr$ is $x + 4(-2) = -2$,so $x = +6$.In $Cr_{2}O_{7}^{2-}$,the oxidation state of $Cr$ is $2x + 7(-2) = -

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The oxidation states of chromium in $CrO_{4}^{2-}$ and $Cr_{2}O_{7}^{2-}$ are not the same.

(A) In $CrO_{4}^{2-}$,the oxidation state of $Cr$ is $x + 4(-2) = -2$,so $x = +6$.In $Cr_{2}O_{7}^{2-}$,the oxidation state of $Cr$ is $2x + 7(-2) = -2$,so $2x = +12$,$x = +6$.Since the oxidation states of chromium in both ions are $+6$,the statement in option $A$ is incorrect.

Class 12 Chemistry d-and f-Block Elements Chemical properties

Medium

Identify the incorrect statement.

NEET 2020 All NEET

A
The oxidation states of chromium in $CrO_{4}^{2-}$ and $Cr_{2}O_{7}^{2-}$ are not the same.
B
$Cr^{2+}(d^{4})$ is a stronger reducing agent than $Fe^{2+}(d^{6})$ in water.
C
The transition metals and their compounds are known for their catalytic activity due to their ability to adopt multiple oxidation states and to form complexes.
D
Interstitial compounds are those that are formed when small atoms like $H, C$ or $N$ are trapped inside the crystal lattices of metals.