Identify the formula of Bis(ethylenediamine)d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The central metal ion is Platinum $(Pt)$ with an oxidation state of $+4$.$2$. The ligand 'ethylenediamine' $(en)$ is a neutral bidentate liga

Vedclass · Accepted Answer

$[Pt(en)_2(SCN)_2]^{2+}$

Vedclass · Answer

(D) $1$. The central metal ion is Platinum $(Pt)$ with an oxidation state of $+4$.$2$. The ligand 'ethylenediamine' $(en)$ is a neutral bidentate ligand,so its charge is $0$.$3$. The ligand 'thiocyanato' $(SCN^-)$ is an anionic ligand with a charge of $-1$.$4$. The complex is 'Bis(ethylenediamine)dithiocyanatoplatinum$(IV)$',which implies two $en$ ligands and two $SCN$ ligands.$5$. The total charge on the complex = (Charge of $Pt$) + $2 	imes$ (Charge of $en$) + $2 	imes$ (Charge of $SCN^-$).$6$. Total charge = $(+4) + 2(0) + 2(-1) = +4 - 2 = +2$.$7$. Therefore,the formula is $[Pt(en)_2(SCN)_2]^{2+}$.

Identify the formula of Bis(ethylenediamine)dithiocyanatoplatinum$(IV)$.

Similar Questions

The formula for the chlorobis(ethylenediamine)nitro-cobalt $(III)$ ion is:

The oxidation number of iron in potassium ferrocyanide is

Oxidation number of $Fe$ in the violet coloured complex $Na_4[Fe(CN)_5(NOS)]$ is:

$[Fe(N_3)(O_2)(SCN)_4]^{4-}$ is named as

$K_2[Zn(OH)_4]$ is the chemical formula for which coordination compound?

Vedclass Test Series

Exam Paper Generator

Online Exam Module