Identify the correct statement from the following properties.

  • A
    Osmosis is a colligative property.
  • B
    The vapour pressure of a solution containing a non-volatile solute is lower than that of the pure solvent at any given temperature.
  • C
    The osmotic pressure of $0.1 \ M$ $NaCl$ solution is lower than $0.1 \ M$ sucrose solution.
  • D
    The boiling point of a solution containing a non-volatile solute is lower than that of the pure solvent.

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At $80^o C$,the vapor pressure of pure liquid $A$ is $520 \ mm \ Hg$ and that of pure liquid $B$ is $1000 \ mm \ Hg$. If a mixture of $A$ and $B$ boils at $80^o C$ and $1 \ atm$ pressure,the mole percentage of $A$ in the mixture is ........... $(1 \ atm = 760 \ mm \ Hg)$.

$1 \, \text{mole}$ of each of $A$ and $B$ form an ideal solution of vapour pressure $100 \, \text{mm Hg}$. Addition of $2 \, \text{moles}$ of $B$ to it decreases the vapour pressure by $20 \, \text{mm Hg}$. The vapour pressure of $A$ and $B$ in pure state are,respectively:

Elevation in boiling point for $1.5 \, m$ solution of glucose in water is $4 \, K$. The depression in freezing point for $4.5 \, m$ solution of glucose in water is $4 \, K$. The ratio of molal elevation constant to molal depression constant $(K_{b} / K_{f})$ is $....$

$A$ solution at $20\,^oC$ is composed of $1.5\,mol$ of benzene and $3.5\,mol$ of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are $74.7\,torr$ and $22.3\,torr,$ respectively,then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be,respectively

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. van't Hoff factor,$i$ $I$. Cryoscopic constant
$B$. $k_{f}$ $II$. Isotonic solutions
$C$. Solutions with same osmotic pressure $III$. $\frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}$
$D$. Azeotropes $IV$. Solutions with same composition of vapour above it

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