Identify the correct statement for the reacti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First,assign oxidation numbers to the elements in the reaction: $I_2^0 + K^{+1}Cl^{+5}O_3^{-2} \rightarrow I^{+1}Cl^{-1} + K^{+1}I^{+5}O_3^{-2}$.I

Vedclass · Accepted Answer

Oxidation number of $Cl$ decreases by $6$

Vedclass · Answer

(C) First,assign oxidation numbers to the elements in the reaction: $I_2^0 + K^{+1}Cl^{+5}O_3^{-2} \rightarrow I^{+1}Cl^{-1} + K^{+1}I^{+5}O_3^{-2}$.In this reaction,$I_2$ (oxidation number $0$) is oxidized to $I^{+1}$ (in $ICl$) and $I^{+5}$ (in $KIO_3$).Since $I_2$ is being oxidized,it acts as a reducing agent.$Cl$ in $KClO_3$ changes from $+5$ to $-1$ (in $ICl$).The change in oxidation number of $Cl$ is $|-1 - 5| = 6$. Thus,the oxidation number of $Cl$ decreases by $6$.Therefore,the statement 'Oxidation number of $Cl$ decreases by $6$' is correct.

Identify the correct statement for the reaction: $I_2 + KClO_3 \xrightarrow{\Delta} ICl + KIO_3$

Similar Questions

One of the products formed due to the reaction between $KMnO_4$ and $HCl$ is

$Cr _2 O _7^{2-} \rightarrow Cr ^{3+}_{aq}$
How many moles of $Sn^{2+}$ will be oxidized by $1 \ mol \ Cr_2O_7^{2-}$ into $Sn^{4+}$?

In the given reaction,calculate the number of electrons lost by iron:
$3Fe + 4H_2O \to Fe_3O_4 + 4H_2$

Which of the following is a redox reaction?

When $H_2S$ is passed through acidified $KMnO_4,$ we get

Vedclass Test Series

Exam Paper Generator

Online Exam Module