Identify the correct order of ionic radii of | vedclass

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(B) The ionic radius of species depends on the effective nuclear charge and the number of shells.For ions with the same number of electrons (isoelectr

Vedclass · Accepted Answer

$S^{2-} > K^{+} > Sc^{3+} > V^{5+} > Mn^{7+}$

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(B) The ionic radius of species depends on the effective nuclear charge and the number of shells.For ions with the same number of electrons (isoelectronic series),the ionic radius decreases as the atomic number increases because the effective nuclear charge increases.Comparing $S^{2-}$ $(18 \ e^-)$ and $K^+$ $(18 \ e^-)$: Since $S^{2-}$ has a lower atomic number $(Z=16)$ than $K^+$ $(Z=19)$,$S^{2-}$ has a larger ionic radius.For the transition metal ions $Sc^{3+}$,$V^{5+}$,and $Mn^{7+}$,as the oxidation state increases,the ionic radius decreases due to the increase in effective nuclear charge and loss of electrons.Thus,the order is $S^{2-} > K^{+} > Sc^{3+} > V^{5+} > Mn^{7+}$.

Identify the correct order of ionic radii of the given species.

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