Identify the correct equation relating Delta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The general relation between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by: $\Delta H = \Delta U + \Delta n_g R

Vedclass · Accepted Answer

$\Delta U = \Delta H - R \Delta T$

Vedclass · Answer

(C) The general relation between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by: $\Delta H = \Delta U + \Delta n_g RT$ For $1 	ext{ mole}$ of an ideal gas undergoing a process where $\Delta n_g = 1$,the equation becomes: $\Delta H = \Delta U + RT$ Rearranging this to solve for $\Delta U$: $\Delta U = \Delta H - RT$ Since $\Delta T$ is the change in temperature,for a process where the change in moles is $1$,the term is $R \Delta T$. Thus,$\Delta U = \Delta H - R \Delta T$.

Identify the correct equation relating $\Delta H$,$\Delta U$,and $\Delta T$ for $1 \text{ mole}$ of an ideal gas from the following $(R = \text{gas constant})$:

Similar Questions

Two moles of an ideal gas expand freely and isothermally from $5 \ dm^3$ to $50 \ dm^3$. What is the value of $\Delta H$?

Explain extensive property and intensive property.

The species which by definition has $ZERO$ standard molar enthalpy of formation at $298 \ K$ is

Two moles of an ideal gas expand spontaneously into a vacuum. The work done is ............. $Joule$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module