Identify the conjugate acid-base pair in the | vedclass

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(B) conjugate acid-base pair differs by a single proton $(H^{+})$. In the reaction $HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(

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$H_3O_{(aq)}^{+}$ and $H_2O_{(l)}$

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(B) conjugate acid-base pair differs by a single proton $(H^{+})$. In the reaction $HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(aq)}^{-}$: $(1)$ $HCl$ acts as an acid and loses a proton to form its conjugate base,$Cl^{-}$. Thus,$(HCl, Cl^{-})$ is a conjugate acid-base pair. $(2)$ $H_2O$ acts as a base and accepts a proton to form its conjugate acid,$H_3O^{+}$. Thus,$(H_2O, H_3O^{+})$ is a conjugate acid-base pair. Comparing this with the options,$(H_2O, H_3O^{+})$ is listed as option $(B)$.

Identify the conjugate acid-base pair in the following reaction: $HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(aq)}^{-}$

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