Identify the compounds A and B involved in th | vedclass

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(C) The given reaction is an aldol condensation. The product is $CH_3-CH_2-CH(OH)-CH(CH_3)-CHO$.To identify the reactants,we break the bond between th

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$CH_3 CH_2 CHO, CH_3 CH_2 CHO$

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(C) The given reaction is an aldol condensation. The product is $CH_3-CH_2-CH(OH)-CH(CH_3)-CHO$.To identify the reactants,we break the bond between the $\alpha$ and $\beta$ carbons relative to the aldehyde group $(-CHO)$.The product is a $\beta$-hydroxy aldehyde. The bond cleavage occurs between the $C_2$ and $C_3$ positions relative to the $-CHO$ group.Breaking the bond at the $C-C$ bond between the $CH(OH)$ and $CH(CH_3)$ groups gives:$1$. $CH_3-CH_2-CHO$ (Propanal) which acts as the nucleophile (enolate donor).$2$. $CH_3-CH_2-CHO$ (Propanal) which acts as the electrophile (carbonyl acceptor).Thus,the reaction is a self-aldol condensation of propanal $(CH_3 CH_2 CHO)$.

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$

Identify the compounds $A$ and $B$ involved in the formation of the given aldol product: $A + B \xrightarrow{OH^-} CH_3-CH_2-CH(OH)-CH(CH_3)-CHO$

Similar Questions

$A$ and $B$ are isomers. Identify $B$.

The starting material is $CH_3COCH_2CHO$. The reaction sequence is:
$CH_3COCH_2CHO$ $\xrightarrow[{(ii)LiAlH_4}]{{(i)ethylene\,glycol/dry\,HCl}} A$ $\xrightarrow[\Delta ]{H_3O^{+}} B$
What will be $B$?

Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

In which of the following reactions is the product $NOT$ correct?

In the above sequence,$P$ and $Q$ products can be distinguished by?

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