Identify the compound which has the maximum n | vedclass

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(D) Key Idea: The number of no-bond resonance (hyperconjugation) structures is equal to the number of $\alpha$-hydrogen atoms present on the carbon at

Vedclass · Accepted Answer

Toluene $(C_6H_5-CH_3)$

Vedclass · Answer

(D) Key Idea: The number of no-bond resonance (hyperconjugation) structures is equal to the number of $\alpha$-hydrogen atoms present on the carbon atom directly attached to the benzene ring.$(a)$ tert-Butylbenzene: The $\alpha$-carbon has $0$ $H$-atoms. Number of hyperconjugation structures = $0$.$(b)$ Ethylbenzene: The $\alpha$-carbon $(CH_2)$ has $2$ $H$-atoms. Number of hyperconjugation structures = $2$.$(c)$ Isopropylbenzene: The $\alpha$-carbon $(CH)$ has $1$ $H$-atom. Number of hyperconjugation structures = $1$.$(d)$ Toluene: The $\alpha$-carbon $(CH_3)$ has $3$ $H$-atoms. Number of hyperconjugation structures = $3$.Since toluene has the maximum number of $\alpha$-hydrogen atoms $(3)$,it has the maximum number of no-bond resonance structures. Hence,option $(d)$ is the correct answer.

Identify the compound which has the maximum number of no-bond resonance (hyperconjugation) structures.

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