Identify the compound $X$ in the following reaction.
Acetone $+ X \stackrel{\Delta}{\longrightarrow} CHI_3 \downarrow + CH_3COONa + 2 NaOH$

Reduction of the lactol $S$ with sodium borohydride $(NaBH_4)$ gives:

Among the following compounds,which will react with acetone to give a product containing $> C = N -$?

Acetone reacts with iodine to form iodoform in the presence of

Match the reactions in Column-$I$ with their products in Column-$II$.
| Column-$I$ (Reagents) | Column-$II$ (Product) |
| :--- | :--- |
| $(A) \ CH_3CHO + 2C_2H_5OH \xrightarrow{HCl_{(g)}} $ | $(i) \ (CH_3)_2C(OCH_2)_2$ |
| $(B) \ CH_3COCH_3 + CH_2OH-CH_2OH \xrightarrow{HCl_{(g)}} $ | $(ii) \ CH_3CH(OH)CN$ |
| $(C) \ CH_3CHO + HCN$ $\xrightarrow{OH^-}$ $\xrightarrow{H_3O^+}$ | $(iii) \ CH_3CH(OC_2H_5)_2$ |
| $(D) \ CH_3CHO + HCN \xrightarrow{OH^-} $ | $(iv) \ CH_3CH(OH)COOH$ |

Describe the various chemical reactions of aldehyde and ketone compounds.