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(A) $1$. The reaction of $1-$methylcyclopentene with dilute alkaline $KMnO_4$ at $273 \ K$ (Baeyer's reagent) is a syn-hydroxylation reaction,which ad

Vedclass · Accepted Answer

$A: 	ext{1-methylcyclopentane-1,2-diol}, B: 	ext{2-hydroxy-2-methylcyclopentanone}$

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(A) $1$. The reaction of $1-$methylcyclopentene with dilute alkaline $KMnO_4$ at $273 \ K$ (Baeyer's reagent) is a syn-hydroxylation reaction,which adds two hydroxyl groups across the double bond to form $1-$methylcyclopentane$-1,2-$diol $(A)$.$2$. The product $A$ is a vicinal diol. The secondary alcohol group is more easily oxidized than the tertiary alcohol group. Treatment with $CrO_3$ (Jones reagent or similar chromium-based oxidant) selectively oxidizes the secondary alcohol to a ketone,resulting in $2-$hydroxy$-2-$methylcyclopentanone $(B)$.

Identify products $A$ and $B$ in the following reaction sequence:
$1$-methylcyclopentene $\xrightarrow{\text{dil. } KMnO_4, 273 \ K} A$ $\xrightarrow{CrO_3} B$

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Identify products $A$ and $B$ in the following reaction sequence:$1$-methylcyclopentene $\xrightarrow{\text{dil. } KMnO_4, 273 \ K} A$ $\xrightarrow{CrO_3} B$