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(C) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ in the presence of a base (like pyridine) leads to the formation of acetanilide ($N

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p-toluidine

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(C) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ in the presence of a base (like pyridine) leads to the formation of acetanilide ($N$-phenylacetamide) via acetylation of the amino group. This protects the amino group and reduces its activating effect.$2$. The subsequent Friedel-Crafts alkylation with $CH_3Cl$ in the presence of $AlCl_3$ occurs at the para-position due to the steric hindrance at the ortho-position and the ortho/para-directing nature of the acetamido group. This yields p-methylacetanilide.$3$. Finally,the acidic hydrolysis $(H^{\oplus}/H_2O)$ of the amide group removes the acetyl protecting group to regenerate the free amino group,resulting in p-toluidine as the final major product.

Identify the major product of the following sequence of reactions:

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