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(A) The $E_2$ reaction involves the abstraction of a $\beta$-hydrogen by a base in the rate-determining step.In these compounds,the $\beta$-atoms are

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$i > ii > iii$

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(A) The $E_2$ reaction involves the abstraction of a $\beta$-hydrogen by a base in the rate-determining step.In these compounds,the $\beta$-atoms are $H$,$D$,and $T$ respectively.The $C-H$ bond is weaker than the $C-D$ bond,which is weaker than the $C-T$ bond due to the primary kinetic isotope effect.Since the $C-H$ bond is the easiest to break,the rate of the $E_2$ reaction follows the order: $H > D > T$.Therefore,the reactivity order is $(i) > (ii) > (iii)$.

Identify the correct order of reactivity for the $E_2$ reaction with alcoholic $KOH$ for the following compounds:
$(i)$ $(CH_3)_3C-Cl$
(ii) $(CD_3)_3C-Cl$
(iii) $(CT_3)_3C-Cl$

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Identify the correct order of reactivity for the $E_2$ reaction with alcoholic $KOH$ for the following compounds:$(i)$ $(CH_3)_3C-Cl$(ii) $(CD_3)_3C-Cl$(iii) $(CT_3)_3C-Cl$