Identify A, B, C and D in the reactions:(I) x | vedclass

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(B) When chlorine reacts with $NaOH$,different products are formed depending upon the temperature and concentration of $NaOH$.For cold and dilute $NaO

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$NaCl, NaOCl, NaCl, NaClO_3$

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(B) When chlorine reacts with $NaOH$,different products are formed depending upon the temperature and concentration of $NaOH$.For cold and dilute $NaOH$:$Cl_2 + 2 NaOH \longrightarrow NaCl + NaOCl + H_2 O$Here,$A = NaCl$ and $B = NaOCl$.For hot and concentrated $NaOH$:$3 Cl_2 + 6 NaOH \longrightarrow 5 NaCl + NaClO_3 + 3 H_2 O$Here,$C = NaCl$ and $D = NaClO_3$.Therefore,the correct sequence is $A = NaCl, B = NaOCl, C = NaCl, D = NaClO_3$.

Identify $A, B, C$ and $D$ in the reactions:
$(I)$ $x Cl_2 + y NaOH \longrightarrow A + B + H_2 O_{(l)}$ (Cold,dil.)
$(II)$ $x Cl_2 + y NaOH \longrightarrow C + D + H_2 O_{(l)}$ (Hot,conc.)

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Identify $A, B, C$ and $D$ in the reactions:$(I)$ $x Cl_2 + y NaOH \longrightarrow A + B + H_2 O_{(l)}$ (Cold,dil.)$(II)$ $x Cl_2 + y NaOH \longrightarrow C + D + H_2 O_{(l)}$ (Hot,conc.)