Identify $(A)$ in the following reaction sequence:
$\mathop {(A)}\limits_{\text{gives positive iodoform Test}}$ $\xrightarrow[(ii) H^{+}, H_2O, (iii) \text{conc. } H_2SO_4/\Delta ]{(i) CH_3MgBr} (B)$ $\xrightarrow{O_3/Zn, H_2O}$

Cyclohexylamine when treated with nitrous acid yields $(P)$. On treating $(P)$ with $PCC$ results in $(Q)$. When $(Q)$ is heated with dilute $NaOH$,we get $(R)$. The final product $(R)$ is:

The product$(s)$ formed when $m$-chlorobenzaldehyde is heated with concentrated $NaOH$ is/are:

Which of the following statements are $TRUE$ about Haloform reaction?
$A$. Sodium hypochlorite reacts with $KI$ to give $KOI$.
$B$. $KOI$ is a reducing agent.
$C$. $\alpha, \beta$-unsaturated methylketone will give iodoform reaction.
$D$. Isopropyl alcohol will not give iodoform test.
$E$. Methanoic acid will give positive iodoform test.
Choose the correct answer from the options given below:

What are $X$ and $Y$ respectively in the following reactions?
$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$
$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$

$(A) Ph-CH(OH)-CHO \xrightarrow[H_2O]{HO^-} (B)$; $(A)$ and $(B)$ are isomers and isomerization is effectively carried out by a trace of base. Identify $(B)$.