Hydrolysis of an alkyl bromide X (C_5H_{11}Br | vedclass

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(D) The hydrolysis of an alkyl bromide $C_5H_{11}Br$ following first-order kinetics indicates an $S_N1$ mechanism,which proceeds via the formation of

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(D) The hydrolysis of an alkyl bromide $C_5H_{11}Br$ following first-order kinetics indicates an $S_N1$ mechanism,which proceeds via the formation of a stable carbocation. For a $C_5$ alkyl bromide to form a stable carbocation,it is likely a tertiary alkyl bromide,specifically $2$-bromo-$2$-methylbutane.$1$. Formation of Grignard reagent: $CH_3CH_2C(CH_3)_2Br + Mg \xrightarrow{	ext{dry ether}} CH_3CH_2C(CH_3)_2MgBr$.$2$. Reaction with $D_2O$: The Grignard reagent reacts with $D_2O$ to replace the $MgBr$ group with a deuterium atom $(D)$: $CH_3CH_2C(CH_3)_2MgBr + D_2O ightarrow CH_3CH_2C(CH_3)_2D + Mg(OD)Br$.Thus,the product $Y$ is $2$-deuterio-$2$-methylbutane,which matches the structure shown in option $D$.

Hydrolysis of an alkyl bromide $X$ $(C_5H_{11}Br)$ follows first-order kinetics. Reaction of $X$ with $Mg$ in dry ether followed by treatment with $D_2O$ gives $Y$. What is $Y$?

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