(N/A) $H_{2}O$ acts as a source of $H^{+}$ and $OH^{-}$. Alkenes react with water in the presence of an acid catalyst like $H_{2}SO_{4}$ to form alcohols through an electrophilic addition reaction. This process follows the Markovnikov rule,where the hydroxyl group $(-OH)$ attaches to the more substituted carbon atom. Examples include:
$1$. $CH_{2}=CH_{2} + H_{2}O \xrightarrow{H^{+}, \Delta} CH_{3}-CH_{2}OH$ (Ethanol)
$2$. $CH_{3}CH=CH_{2} + H_{2}O \xrightarrow{H^{+}} CH_{3}-CH(OH)-CH_{3}$ (Propane$-2-$ol)
$3$. $CH_{3}-C(CH_{3})=CH_{2} + H_{2}O \xrightarrow{H^{+}} CH_{3}-C(OH)(CH_{3})-CH_{3}$ ($2$-Methylpropane$-2-$ol)