Hydrogen iodide cannot be prepared by the act | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When $KI$ reacts with concentrated $H_2SO_4$,$HI$ is initially formed as $KI + H_2SO_4 \rightarrow KHSO_4 + HI$. However,$HI$ is a strong reducing

Vedclass · Accepted Answer

$H_2SO_4$ is an oxidising agent

Vedclass · Answer

(C) When $KI$ reacts with concentrated $H_2SO_4$,$HI$ is initially formed as $KI + H_2SO_4 \rightarrow KHSO_4 + HI$. However,$HI$ is a strong reducing agent and concentrated $H_2SO_4$ is a strong oxidising agent. Therefore,$H_2SO_4$ oxidizes $HI$ to $I_2$ according to the reaction: $2HI + H_2SO_4 \rightarrow I_2 + SO_2 + 2H_2O$. Thus,$HI$ cannot be prepared by this method.

Hydrogen iodide cannot be prepared by the action of concentrated $H_2SO_4$ on potassium iodide because:

Similar Questions

Which of the following is used for the extraction of glue from bones?

What is the sum of the number of neutrons and protons in the heaviest isotope of hydrogen?

What do you understand by $(i)$ electron-deficient,$(ii)$ electron-precise,and $(iii)$ electron-rich compounds of hydrogen? Provide justification with suitable examples.

The basic principle of the hydrogen economy is the transportation and storage of energy in the form of liquid or gaseous hydrogen. Which property of hydrogen may be useful for this purpose? Support your answer with a chemical equation if required.

Calorific value of producer gas is low because of

Vedclass Test Series

Exam Paper Generator

Online Exam Module