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(B) The three isotopes of hydrogen are $H^1$ (Protium),$H^2$ (Deuterium),and $H^3$ (Tritium).For a diatomic molecule $XY$,the number of possible combi

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$6$

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(B) The three isotopes of hydrogen are $H^1$ (Protium),$H^2$ (Deuterium),and $H^3$ (Tritium).For a diatomic molecule $XY$,the number of possible combinations is given by the formula $\frac{n(n+1)}{2}$,where $n$ is the number of isotopes.Here,$n = 3$.Number of molecules = $\frac{3(3+1)}{2} = \frac{3 	imes 4}{2} = 6$.The possible molecules are: $H^1H^1, H^1H^2, H^1H^3, H^2H^2, H^2H^3, H^3H^3$.

Hydrogen has three isotopes. The number of possible diatomic molecules will be:

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