Hydrogen gas is not liberated when the following metal is added to dil $HCl$.

  • A
    $Ag$
  • B
    $Zn$
  • C
    $Mg$
  • D
    $Sn$

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Given $E^{0}_{Fe^{3+}|Fe} = -0.036 \, V$ and $E^{0}_{Fe^{2+}|Fe} = -0.439 \, V$,the standard electrode potential for the reaction $Fe^{3+}_{(aq)} + e^{-} \rightarrow Fe^{2+}_{(aq)}$ is ........... $V$.

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What is to be done to determine the potential of any half cell?

Using the standard electrode potentials given below,identify the correct statements from the following.
$Fe^{2+} + 2e^{-} \longrightarrow Fe ; E^{\circ} = -0.44 \ V$
$Cu^{2+} + 2e^{-} \longrightarrow Cu ; E^{\circ} = +0.34 \ V$
$Ag^{+} + e^{-} \longrightarrow Ag ; E^{\circ} = +0.80 \ V$
$(i)$ Copper can displace iron from $FeSO_4$ solution.
$(ii)$ Iron can displace copper from $CuSO_4$ solution.
$(iii)$ Silver can displace copper from $CuSO_4$ solution.
$(iv)$ Iron can displace silver from $AgNO_3$ solution.

Assume the cell reaction,$A_{(s)} + B_{(aq)}^{+2} \rightarrow A_{(aq)}^{+2} + B_{(s)}$. If $\Delta G^{\circ} = -386 \ kJ$ at $298 \ K$,what is $E_{\text{cell}}^{\circ}$ (in $V$)? (Assume $n = 2$)

The oxidation potentials of $Zn, Cu, Ag, H_2$ and $Ni$ are $0.76, -0.34, -0.80, 0$ and $0.25 \ V$ respectively. Which reaction provides the maximum voltage?

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