Hydrogen gas diffuses six times faster than g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$.Given that the rate of diffusion of hydrogen $(r_H)$ is $6$ times the rate of diffusion of gas $A$ $(r_A)$,we have $r_H = 6r_A$.The molar mass of hydrogen $(H_2)$ is $M_H = 2 \ g/mol$.Substituting these values into the formula: $\frac{r_H}{r_A} = \sqrt{\frac{M_A}{M_H}}$.$6 = \sqrt{\frac{M_A}{2}}$.Squaring both sides: $36 = \frac{M_A}{2}$.Therefore,$M_A = 36 	imes 2 = 72 \ g/mol$.

Hydrogen gas diffuses six times faster than gas $A$. The molar mass of gas $A$ is

Similar Questions

At $100\,^oC$ and $1\, atm$ pressure,the density of liquid water is $1.0\, g\, cm^{-3}$ and the density of water vapor is $0.0006\, g\, cm^{-3}$. What is the volume occupied by water molecules in $1\, L$ of steam at the same temperature in $cm^3$?

Which of the following is not considered in the calculation of the rate of diffusion according to Graham's Law?

Explain the vapour pressure of a liquid.

$40 \ mL$ of hydrogen diffuses through a fine hole in $25 \ min$. How much time (in $min$) will $20 \ mL$ of oxygen take to diffuse under the same conditions?

If two gases $CH_4$ and $SO_2$ are allowed to enter from the two ends of a $1 \ km$ long vacuum tube at the same time,where will the gases meet from the $CH_4$ end (in $m$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module