What is the hybridisation of carbon C_2 and C | vedclass

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(D) The given molecule is $CH_3-CH=CH-CH_3$. Numbering the carbons from left to right: $C_1$ is $CH_3$ (attached to $C_2$ by a single bond). $C_2$ is

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$sp^2$ and $sp^3$

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(D) The given molecule is $CH_3-CH=CH-CH_3$. Numbering the carbons from left to right: $C_1$ is $CH_3$ (attached to $C_2$ by a single bond). $C_2$ is $CH$ (attached to $C_1$ by a single bond and $C_3$ by a double bond). $C_3$ is $CH$ (attached to $C_2$ by a double bond and $C_4$ by a single bond). $C_4$ is $CH_3$ (attached to $C_3$ by a single bond). For $C_2$: It is bonded to one $H$ atom,one $C_1$ atom (single bond),and one $C_3$ atom (double bond). It has $3$ sigma bonds and $0$ lone pairs,so it is $sp^2$ hybridised. For $C_4$: It is bonded to three $H$ atoms and one $C_3$ atom (single bond). It has $4$ sigma bonds and $0$ lone pairs,so it is $sp^3$ hybridised. Therefore,the hybridisation of $C_2$ and $C_4$ is $sp^2$ and $sp^3$ respectively.

Column-$I$	Column-$II$
$A$. Boron in $[B(OH)_4]^-$	$1$. $sp^2$
$B$. Aluminum in $[Al(H_2O)_6]^{3+}$	$2$. $sp^3$
$C$. Boron in $B_2H_6$	$3$. $sp^3d^2$
$D$. Carbon in Buckminsterfullerene
$E$. $Si$ in $SiO_4^{4-}$
$F$. $Ge$ in $[GeCl_6]^{2-}$

What is the hybridisation of carbon $C_2$ and $C_4$ respectively in the molecule $CH_3-CH=CH-CH_3$?

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