What is the hybridisation and shape of Cr in | vedclass

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(A) In chromyl chloride $(CrO_2Cl_2)$,the oxidation state of Chromium $(Cr)$ is $+6$.The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.For $Cr^

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$sp^3$,Tetrahedral

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(A) In chromyl chloride $(CrO_2Cl_2)$,the oxidation state of Chromium $(Cr)$ is $+6$.The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.For $Cr^{6+}$,the configuration is $[Ar] 3d^0 4s^0$.Chromium forms two double bonds with oxygen atoms and two single bonds with chlorine atoms.There are $4$ sigma bonds and $2$ pi bonds around the central $Cr$ atom.Since there are $4$ sigma bonds and no lone pairs,the hybridisation is $sp^3$.The shape corresponding to $sp^3$ hybridisation with $4$ bonding pairs is Tetrahedral.

List-$I$ (Complex)	List-$II$ (Hybridization)
$A. Ni(CO)_4$	$I. sp^3d^2$
$B. [Ni(CN)_4]^{2-}$	$II. d^2sp^3$
$C. [Co(NH_3)_6]^{3+}$	$III. dsp^2$
$D. [CoF_6]^{3-}$	$IV. sp^3$

What is the hybridisation and shape of $Cr$ in chromyl chloride $(CrO_2Cl_2)$?

Similar Questions

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List-$I$ (Complex) List-$II$ (Hybridization)
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