How would you account for the increasing oxidising power in the series $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The oxidising power of these oxoanions depends on the stability of the lower oxidation states to which they are reduced.
As we move from $VO_2^+$ to $MnO_4^-$,the stability of the reduced species increases,which makes the reduction of the parent oxoanion more favorable.
Specifically,the reduction potentials increase in the order $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$,reflecting the increasing ease with which these species accept electrons.

Explore More

Similar Questions

$Cu^{2+}$ salt reacts with potassium iodide to give :

Which of the following oxidation states of manganese exhibits the most powerful oxidizing property?

Select the incorrect statement.

Difficult
View Solution

The highest oxidation state of manganese in fluoride is $+4$ $(MnF_4)$,but the highest oxidation state in oxides is $+7$ $(Mn_2O_7)$ because __

Difficult
View Solution

Which of these statements is not true?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo