How will you separate a miscible solution of | vedclass

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(C) Distillation,specifically fractional distillation,is used because the boiling points of benzene $(80\,^{\circ}C)$ and chloroform $(61.5\,^{\circ}C

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Distillation

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(C) Distillation,specifically fractional distillation,is used because the boiling points of benzene $(80\,^{\circ}C)$ and chloroform $(61.5\,^{\circ}C)$ are relatively close.Fractional distillation involves repeated distillations and condensations within a fractionating column.As a result of these processes at each point in the column,the vapors rising up become richer in the more volatile component (chloroform),while the liquid falling back into the flask becomes richer in the less volatile component (benzene).Thus,the liquid with the lower boiling point distills first,followed by the liquid with the higher boiling point.

How will you separate a miscible solution of benzene and $CHCl_3$?

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