How much momentum will a dumbbell of mass 10 | vedclass

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(B) Given: Mass $(m) = 10 \, kg$,Initial velocity $(u) = 0 \, m s^{-1}$,Height $(S) = 0.8 \, m$,Acceleration due to gravity $(g) = 10 \, m s^{-2}$.Usi

Vedclass · Accepted Answer

$40 \, kg \, m s^{-1}$

Vedclass · Answer

(B) Given: Mass $(m) = 10 \, kg$,Initial velocity $(u) = 0 \, m s^{-1}$,Height $(S) = 0.8 \, m$,Acceleration due to gravity $(g) = 10 \, m s^{-2}$.Using the equation of motion $v^2 - u^2 = 2gS$:$v^2 - (0)^2 = 2 	imes 10 	imes 0.8$$v^2 = 16$$v = 4 \, m s^{-1}$.Momentum $(p)$ is defined as the product of mass and velocity:$p = m 	imes v$$p = 10 \, kg 	imes 4 \, m s^{-1} = 40 \, kg \, m s^{-1}$ (or $40 \, N s$).Thus,the dumbbell will transfer $40 \, kg \, m s^{-1}$ of momentum to the floor.

How much momentum will a dumbbell of mass $10 \, kg$ transfer to the floor,if it falls from a height of $0.8 \, m$? Take acceleration due to gravity as $10 \, m s^{-2}$.

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