How much heat energy is supplied when 5 ,kg o | vedclass

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(A) Given that,mass $m = 5 \,kg = 5000 \,g$. Specific heat capacity $c = 4.2 \,J / g^{\circ} C$. Initial temperature $T_1 = 20^{\circ} C$. Boiling poi

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$1680$ kJ

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(A) Given that,mass $m = 5 \,kg = 5000 \,g$. Specific heat capacity $c = 4.2 \,J / g^{\circ} C$. Initial temperature $T_1 = 20^{\circ} C$. Boiling point of water $T_2 = 100^{\circ} C$. Change in temperature $\Delta T = T_2 - T_1 = 100^{\circ} C - 20^{\circ} C = 80^{\circ} C$. The heat energy supplied is given by the formula $\Delta Q = m c \Delta T$. Substituting the values: $\Delta Q = 5000 \,g 	imes 4.2 \,J / g^{\circ} C 	imes 80^{\circ} C$. $\Delta Q = 5000 	imes 4.2 	imes 80 = 1680000 \,J$. Converting to kilojoules: $\Delta Q = 1680 \,kJ$.

How much heat energy is supplied when $5 \,kg$ of water at $20^{\circ} C$ is brought to its boiling point? (Assume,specific heat of water $=4.2 \,J / g^{\circ} C$ )

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