Difficult
How much copper can be obtained from $100 \, g$ of copper sulphate $(CuSO_{4})$?
(N/A) $1$ mole of $CuSO_{4}$ contains $1$ mole of copper.
Molar mass of $CuSO_{4} = 63.5 + 32.00 + 4(16.00) = 159.5 \, g/mol$.
$159.5 \, g$ of $CuSO_{4}$ contains $63.5 \, g$ of copper.
Therefore,$100 \, g$ of $CuSO_{4}$ will contain $\frac{63.5 \times 100}{159.5} \, g$ of copper.
Amount of copper $= 39.81 \, g$.
Molar mass of $CuSO_{4} = 63.5 + 32.00 + 4(16.00) = 159.5 \, g/mol$.
$159.5 \, g$ of $CuSO_{4}$ contains $63.5 \, g$ of copper.
Therefore,$100 \, g$ of $CuSO_{4}$ will contain $\frac{63.5 \times 100}{159.5} \, g$ of copper.
Amount of copper $= 39.81 \, g$.
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