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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of a photoelectron is given by: $K_{max} = h
u - \Phi_0$ wh

Vedclass · Accepted Answer

It depends linearly on frequency; it does not depend on the intensity of incident light.

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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of a photoelectron is given by: $K_{max} = h
u - \Phi_0$ where $h$ is Planck's constant,$
u$ is the frequency of incident radiation,and $\Phi_0$ is the work function of the metal. $1$. Dependence on frequency: The equation shows that $K_{max}$ increases linearly with the frequency $(
u)$ of the incident radiation. $2$. Independence: $K_{max}$ does not depend on the intensity of the incident radiation,as intensity only affects the number of photoelectrons emitted per second,not their individual kinetic energies.

How does the maximum kinetic energy of a photoelectron depend on the frequency of incident radiation? On which factors does it not depend?

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