How many types of carbon atoms are present in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The structure of $2,2,3-$trimethylpentane is $CH_3-C(CH_3)_2-CH(CH_3)-CH_2-CH_3$. We identify the types of carbon atoms based on their environment

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The structure of $2,2,3-$trimethylpentane is $CH_3-C(CH_3)_2-CH(CH_3)-CH_2-CH_3$. We identify the types of carbon atoms based on their environment: $1$. Primary $(1^{\circ})$ carbons: The terminal $CH_3$ groups at positions $1, 2, 2, 3, 5$ are not all equivalent. $2$. The $CH_3$ attached to $C-2$ are equivalent. $3$. The $CH_3$ attached to $C-3$ is different. $4$. The $CH_3$ at the end of the chain $(C-5)$ is different. $5$. The $CH_2$ at $C-4$ is unique. $6$. The $CH$ at $C-3$ is unique. $7$. The quaternary carbon at $C-2$ is unique. Counting the distinct chemical environments for carbon atoms,we find $4$ types: Type $1$: $CH_3$ groups attached to $C-2$. Type $2$: $CH_3$ group attached to $C-3$. Type $3$: $CH_3$ group at $C-5$. Type $4$: The $CH_2$ group at $C-4$. Type $5$: The $CH$ group at $C-3$. Type $6$: The quaternary carbon at $C-2$. Wait,let us re-evaluate: $C-1$ ($CH_3$ on $C-2$): $1^{\circ}$ $C-2$ (Quaternary): $4^{\circ}$ $C-3$ (Tertiary): $3^{\circ}$ $C-4$ (Secondary): $2^{\circ}$ $C-5$ (Primary): $1^{\circ}$ $CH_3$ on $C-2$: $1^{\circ}$ $CH_3$ on $C-3$: $1^{\circ}$ There are $4$ types of carbon atoms based on degree of substitution $(1^{\circ}, 2^{\circ}, 3^{\circ}, 4^{\circ})$.

How many types of carbon atoms are present in $2,2,3-$trimethylpentane?

Similar Questions

The alkane formed on heating sodium butanoate with sodalime is

$R^{\prime}-X \xrightarrow{Na / \text{ether}} 2,3-\text{dimethylbutane}$. Identify $R^{\prime}$.

Which one of the following compounds does not decolourize bromine water?

In which of the following substances is the carbon atom arranged in a regular tetrahedral structure?

What is the product of the reaction: $CH_3CH_3 + HNO_3 \xrightarrow{675 \ K}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module