How many triangles can be formed by joining f | vedclass

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(A) To form a triangle,we need to select $3$ non-collinear points.Since all points lie on a circle,no three points are collinear.Therefore,the number

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$4$

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(A) To form a triangle,we need to select $3$ non-collinear points.Since all points lie on a circle,no three points are collinear.Therefore,the number of triangles that can be formed by selecting $3$ points out of $4$ is given by the combination formula $^nC_r = \frac{n!}{r!(n-r)!}$.Here,$n = 4$ and $r = 3$.Number of triangles = $^4C_3 = \frac{4!}{3!(4-3)!} = \frac{4 	imes 3 	imes 2 	imes 1}{(3 	imes 2 	imes 1) 	imes 1} = 4$.

How many triangles can be formed by joining four points on a circle?

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