How many terms are there in the series 201, 2 | vedclass

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(C) The given series is an Arithmetic Progression $(A.P.)$ where the first term $a = 201$ and the common difference $d = 208 - 201 = 7$.Let the number

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) The given series is an Arithmetic Progression $(A.P.)$ where the first term $a = 201$ and the common difference $d = 208 - 201 = 7$.Let the number of terms be $n$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the given values: $369 = 201 + (n - 1) 	imes 7$.Subtracting $201$ from both sides: $369 - 201 = (n - 1) 	imes 7$.$168 = (n - 1) 	imes 7$.Dividing by $7$: $n - 1 = 168 / 7 = 24$.Therefore,$n = 24 + 1 = 25$.

How many terms are there in the series $201, 208, 215, \dots, 369$?

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