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(B) To find the number of pairs of letters in the word $PHYSICAL$ that have the same number of letters between them as in the English alphabet,we chec

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(B) To find the number of pairs of letters in the word $PHYSICAL$ that have the same number of letters between them as in the English alphabet,we check both forward and backward directions:$1$. Word: $P, H, Y, S, I, C, A, L$$2$. Forward direction:- $P$ to $H, Y, S, I, C, A, L$: No pairs found.- $H$ to $Y, S, I, C, A, L$: No pairs found.- $Y$ to $S, I, C, A, L$: No pairs found.- $S$ to $I, C, A, L$: No pairs found.- $I$ to $C, A, L$: No pairs found.- $C$ to $A, L$: No pairs found.- $A$ to $L$: No pairs found.$3$. Backward direction:- $L$ to $A, C, I, S, Y, H, P$: $L$ to $A$ (no),$L$ to $C$ (no),$L$ to $I$ (no),$L$ to $S$ (no),$L$ to $Y$ (no),$L$ to $H$ (no),$L$ to $P$ (no).- $A$ to $C, I, S, Y, H, P$: $A$ to $C$ (one letter $B$ in alphabet,but none here),$A$ to $I$ (no).- $C$ to $I, S, Y, H, P$: $C$ to $I$ (no).- $I$ to $S, Y, H, P$: $I$ to $S$ (no).- $S$ to $Y, H, P$: $S$ to $Y$ (no).- $Y$ to $H, P$: $Y$ to $H$ (no).- $H$ to $P$: $H$ to $P$ (in alphabet $H, I, J, K, L, M, N, O, P$ - $7$ letters between them; in word $H, Y, S, I, C, A, L, P$ - $6$ letters between them,no).Wait,let's re-check: $P(16), H(8), Y(25), S(19), I(9), C(3), A(1), L(12)$.Checking pairs: $(I, L)$ - $I(9)$ and $L(12)$. Between them are $J, K$ ($2$ letters). In the word $PHYSICAL$,between $I$ and $L$ are $C, A$ ($2$ letters). Thus,$(I, L)$ is one pair.Therefore,there is only one such pair.

How many such pairs of letters are there in the word $PHYSICAL$,each of which has as many letters between them in the word as they have in the English alphabet?

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