How many such digits are there in the number | vedclass

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(C) The original number is $8, 3, 1, 6, 5$.Arrange the digits of the number in ascending order: $1, 3, 5, 6, 8$.Now,compare the positions of the digit

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Two

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(C) The original number is $8, 3, 1, 6, 5$.Arrange the digits of the number in ascending order: $1, 3, 5, 6, 8$.Now,compare the positions of the digits in both arrangements:Original: $8, 3, 1, 6, 5$Ascending: $1, 3, 5, 6, 8$Comparing the positions:- $1^{st}$ digit: $8 
eq 1$- $2^{nd}$ digit: $3 = 3$ (Match)- $3^{rd}$ digit: $1 
eq 5$- $4^{th}$ digit: $6 = 6$ (Match)- $5^{th}$ digit: $5 
eq 8$The digits $3$ and $6$ remain in the same position.Therefore,there are $2$ such digits.

How many such digits are there in the number $8,3,1,6,5$ each of which is as far away from the beginning of the number as when the digits are rearranged in ascending order within the number?

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How many such digits are there in the number $8,3,1,6,5$ each of which is as far away from the beginning of the number as when the digits are rearranged in ascending order within the number?

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