How many stereoisomers does this molecule hav | vedclass

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(C) The molecule is $CH_3-CH=CH-CH_2-CH(Br)-CH_3$.It contains one chiral center $(n=1)$ and one double bond capable of geometrical isomerism $(m=1)$.T

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$4$

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(C) The molecule is $CH_3-CH=CH-CH_2-CH(Br)-CH_3$.It contains one chiral center $(n=1)$ and one double bond capable of geometrical isomerism $(m=1)$.The chiral center can exist in two configurations ($R$ and $S$),giving $2^1 = 2$ optical isomers.The double bond can exist in two configurations ($cis$ and $trans$),giving $2^1 = 2$ geometrical isomers.Since the chiral center and the double bond are not symmetrically related,the total number of stereoisomers is $2^n 	imes 2^m = 2^1 	imes 2^1 = 4$.

How many stereoisomers does this molecule have?
$CH_3CH=CHCH_2CH(Br)CH_3$

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How many stereoisomers does this molecule have?$CH_3CH=CHCH_2CH(Br)CH_3$