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(A) The area of canvas required for a conical tent is equal to its curved surface area,which is given by the formula $\pi r l$.First,we calculate the

Vedclass · Accepted Answer

$471.42$

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(A) The area of canvas required for a conical tent is equal to its curved surface area,which is given by the formula $\pi r l$.First,we calculate the slant height $(l)$ using the formula $l = \sqrt{r^{2} + h^{2}}$,where $r = 12 \, m$ and $h = 3.5 \, m$.$l = \sqrt{(12)^{2} + (3.5)^{2}} = \sqrt{144 + 12.25} = \sqrt{156.25} = 12.5 \, m$.Now,calculate the curved surface area:Area $= \pi r l = \frac{22}{7} 	imes 12 	imes 12.5$.Area $= \frac{22 	imes 150}{7} \approx 471.428 \, m^{2}$.Rounding to two decimal places,the area required is $471.42 \, m^{2}$.

How many square metres of canvas is required for a conical tent whose height is $3.5 \, m$ and the radius of the base is $12 \, m$ (in $, m^{2}$)?

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