How many roots does the equation x - frac{2}{ | vedclass

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(D) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.For the expression to be defined,the denominator must not be zero,so $x - 1 
eq 0

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(D) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.For the expression to be defined,the denominator must not be zero,so $x - 1 
eq 0$,which implies $x 
eq 1$.Adding $\frac{2}{x - 1}$ to both sides of the equation,we get $x = 1$.However,we have the condition $x 
eq 1$ from the original equation.Since the only potential solution $x = 1$ is excluded by the domain of the equation,there are no roots.

How many roots does the equation $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$ have?

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