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(B) The spin-only magnetic moment is given by the formula $\mu_{s} = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.						Ion Confi

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$2$

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(B) The spin-only magnetic moment is given by the formula $\mu_{s} = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.						Ion Configuration			$n$							$V^{3+}: [Ar] 3d^{2}$			$2$							$Cr^{3+}: [Ar] 3d^{3}$			$3$							$Fe^{2+}: [Ar] 3d^{6}$			$4$							$Ni^{3+}: [Ar] 3d^{7}$			$3$			Comparing the values of $n$,we see that $Cr^{3+}$ and $Ni^{3+}$ both have $n = 3$,meaning they have the same spin-only magnetic moment. Thus,there are $2$ such ions.

How many of the following metal ions have similar values of spin-only magnetic moment in the gaseous state?
(Given: Atomic number: $V, 23; Cr, 24; Fe, 26; Ni, 28$)
$V^{3+}, Cr^{3+}, Fe^{2+}, Ni^{3+}$

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How many of the following metal ions have similar values of spin-only magnetic moment in the gaseous state?(Given: Atomic number: $V, 23; Cr, 24; Fe, 26; Ni, 28$)$V^{3+}, Cr^{3+}, Fe^{2+}, Ni^{3+}$