For the transition elements Cr, Mn, Fe, and C | vedclass

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(B) The standard electrode potential $E^o_{M^{2+}/M}$ values for the transition elements depend on the sum of enthalpy of sublimation,ionization entha

Vedclass · Accepted Answer

$Mn > Cr > Fe > Co$

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(B) The standard electrode potential $E^o_{M^{2+}/M}$ values for the transition elements depend on the sum of enthalpy of sublimation,ionization enthalpy,and hydration enthalpy.For $Mn^{2+}$,the electronic configuration is $3d^5$,which is stable due to the half-filled $d$-subshell,making the reduction potential $E^o_{Mn^{2+}/Mn}$ more negative $(-1.18 \ V)$.For $Cr^{2+}$,the configuration is $3d^4$ $(-0.91 \ V)$.For $Fe^{2+}$,the configuration is $3d^6$ $(-0.44 \ V)$.For $Co^{2+}$,the configuration is $3d^7$ $(-0.28 \ V)$.The magnitude of the negative value follows the order: $Mn > Cr > Fe > Co$.

For the transition elements $Cr, Mn, Fe,$ and $Co$,the correct order of the negative values of $E^o_{M^{2+}/M}$ is:

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