How many minimum numbers of C-atom containing | vedclass

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(B) For a molecule to show optical isomerism,it must be chiral,meaning it must possess at least one chiral center.$A$ chiral center is a carbon atom b

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$4$

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(B) For a molecule to show optical isomerism,it must be chiral,meaning it must possess at least one chiral center.$A$ chiral center is a carbon atom bonded to four different groups.In the case of a monohaloalkane with the general formula $C_nH_{2n+1}X$,we need to find the smallest alkane chain that can accommodate a chiral center.For $n=1$ (chloromethane) and $n=2$ (chloroethane),all carbons are bonded to at least two identical hydrogen atoms.For $n=3$ (chloropropane),$1$-chloropropane has no chiral center,and $2-$chloropropane has two identical methyl groups attached to the central carbon.For $n=4$,$2$-chlorobutane $(CH_3-CHCl-CH_2-CH_3)$ has a chiral center at the $C-2$ position because it is bonded to four different groups: $-H$,$-Cl$,$-CH_3$,and $-CH_2CH_3$.Therefore,the minimum number of carbon atoms required is $4$.

How many minimum numbers of $C$-atom containing monohaloalkane shows optical isomerism?

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