How many lone pairs of electrons are present | vedclass

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(B) The chemical formula for hypochlorous acid is $HOCl$.In this molecule,the chlorine atom is bonded to one oxygen atom and one hydrogen atom.The val

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$3$

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(B) The chemical formula for hypochlorous acid is $HOCl$.In this molecule,the chlorine atom is bonded to one oxygen atom and one hydrogen atom.The valence shell configuration of chlorine is $3s^2 3p^5$.Chlorine forms one single bond with oxygen $(Cl-O)$ and one single bond with hydrogen is not present; rather,the structure is $H-O-Cl$.In $H-O-Cl$,the oxygen atom is bonded to both $H$ and $Cl$.Oxygen has $2$ lone pairs,and chlorine,having $7$ valence electrons,uses $1$ electron for bonding with oxygen,leaving $6$ electrons as $3$ lone pairs on the chlorine atom.

List-$I$	List-$II$
$A$. $XeF_4$	$1$. Pyramidal
$B$. $XeF_6$	$2$. $T$-shape
$C$. $XeO_3$	$3$. Distorted octahedral
$D$. $XeOF_2$	$4$. Square planar

How many lone pairs of electrons are present on the chlorine atom in hypochlorous acid $(HOCl)$?

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Select the correct matching:

List-$I$ List-$II$

$A$. $XeF_4$ $1$. Pyramidal

$B$. $XeF_6$ $2$. $T$-shape

$C$. $XeO_3$ $3$. Distorted octahedral

$D$. $XeOF_2$ $4$. Square planar

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