How many stereoisomers are possible for the f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given molecule is $4$-methylcyclohexylidene-but$-2-$enoic acid.It contains two stereogenic centers/elements that can exhibit geometrical isome

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The given molecule is $4$-methylcyclohexylidene-but$-2-$enoic acid.It contains two stereogenic centers/elements that can exhibit geometrical isomerism:$1$. The exocyclic double bond on the cyclohexane ring: Since the ring is substituted at the $4$-position with a methyl group,the exocyclic double bond can exhibit geometrical isomerism ($E/Z$ or $cis/trans$ relative to the ring substituents).$2$. The double bond in the side chain $(-CH=CH-)$: This double bond can also exhibit geometrical isomerism ($E/Z$ or $cis/trans$).Since both stereogenic elements are independent and can each exist in two configurations,the total number of stereoisomers is $2^n$,where $n=2$.Total stereoisomers = $2^2 = 4$.

How many stereoisomers are possible for the following molecule?

Similar Questions

If $a = i + j + k$,$a \cdot b = 1$ and $a \times b = j - k$,then $b = \dots$

$\lim _{x \rightarrow \infty}\left[\sqrt{x^2+2 x-1}-x\right]$ is equal to :

$\lim _{x \rightarrow \infty}\left(\frac{x+6}{x+1}\right)^{x+4}$ is equal to

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

If $x = \frac{1}{2} \left( \sqrt{3} + \frac{1}{\sqrt{3}} \right)$,then the value of $\frac{\sqrt{x^2 - 1}}{x - \sqrt{x^2 - 1}}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module